17y-y^2=16

Solution for 17y-y^2=16 equation:

17y-y^2=16

We move all terms to the left:

17y-y^2-(16)=0

We add all the numbers together, and all the variables

-1y^2+17y-16=0

a = -1; b = 17; c = -16;
Δ = b2-4ac
Δ = 172-4·(-1)·(-16)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-15}{2*-1}=\frac{-32}{-2}
=+16
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+15}{2*-1}=\frac{-2}{-2}
=1
$